There are orbs on an NxM board ('O' denotes orb. 'X' denotes empty slot).
Whenever two orbs are in the same column or the same row, you get to erase one of them.
Try to erase as many orbs as possible.
Find the minimum number of orbs remained on board eventually.e.g.
OXOXXO XXXXXO XXXXOXerase (0,0) and get
XXOXXO XXXXXO XXXXOXerase (2,0) and get
XXXXXO XXXXXO XXXXOXerase (5,0) and get
XXXXXX XXXXXO XXXXOXno more moves available. Return 2 e.g.
OXOXXO XXXXXO XXOXOX
erase(4,2), (2,2), (0,0), (2,0), (5,0)
OXOXXX XOXXXO XXXOOX
erase(0,0), (1,1), (3,2)
Follow-up Build a solver for this board game that erases the as many orbs as possible.
def solve(board): m, n = len(board), len(board) '''create adjacency list rows has all the nodes in 1st row rows has all the nodes in 2nd row etc. cols has all the nodes in 1st column cols has all the nodes in 2nd column etc.''' rows, cols = [set() for i in range(m)], [set() for j in range(n)] for i in range(m): for j in range(n): if board[i][j] is 'O': rows[i].add(j) cols[j].add(i) #count the degree (number of neighbors) of every orb degrees = dict() for i in range(m): for j in rows[i]: degree = len(rows[i]) + len(cols[j]) - 2 if degree > 0: degrees[(i, j)] = degrees #erase the node with minimum positive degree until all nodes have 0 degree while degrees: erase_orb(degrees, board, rows, cols) #output for row in board: print row #erase the orb with the minimum degree def erase_orb(degrees, board, rows, cols): #find the node with minimum positive degree i, j = min(degrees.items(), key=lambda x: x) #erase this node rows[i].remove(j) cols[j].remove(i) degrees.pop((i, j)) board[i][j] = 'X' print 'erase ', (i, j) #remove one degree from every neighbor of the node erased for y in rows[i]: degrees[(i, y)] -= 1 if degrees[(i, y)] is 0: degrees.pop((i, y)) for x in cols[j]: degrees[(x, j)] -= 1 if degrees[(x, j)] is 0: degrees.pop((x, j)) solve([ ['X', 'X', 'X', 'X', 'X', 'O'], ['O', 'X', 'X', 'X', 'X', 'X'], ['O', 'X', 'X', 'X', 'X', 'O'], ['X', 'X', 'O', 'X', 'O', 'X'], ['X', 'O', 'X', 'X', 'X', 'O'] ])
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